Y=3^3+2x^2

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Solution for Y=3^3+2x^2 equation: 



=3^3+2Y^2

We move all terms to the left:

-(3^3+2Y^2)=0

We get rid of parentheses

-2Y^2-3^3=0

We add all the numbers together, and all the variables

-2Y^2-27=0

a = -2; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·(-2)·(-27)
Δ = -216
Delta is less than zero, so there is no solution for the equation

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